Cos test

Deprecated in Current ReleaseRequirementsSoftware operationDefining Calibration TasksDefinitions and TheorySupported SystemsSupported TargetsRequired EvidenceTest SetupCalibration ProcedureUser InterfaceUse in Imatest ITModule settingsModule outputsDefining a DeviceDefining DistortionDefining the System of DevicesDefining the TargetDefining a Test CaptureDefining a Test ImageHomogenous CoordinatesProjective Camera ModelMulti-Camera SystemsDistortion ModelsCoordinate SystemsRotations and TranslationsTranslationsLet \(\mathbf{X}=\left[\begin{array}{ccc}X&Y&Z\end{array}\right]^{\top}\) be a point in \(\mathbb{R}^3\) and let \(\mathbf{X}’=\left[\begin{array}{ccc}X’&Y’&Z’\end{array}\right]^{\top}\) be \(\mathbf{X}\) after a translation by \(\left[\begin{array}{ccc}\Delta X&\Delta Y&\Delta Z\end{array}\right]^{\top}\). Translations may be represented by a single \(4\times4\) matrix acting on a \(4\times1\) homogeneous coordinate. \(\begin{bmatrix}X’\\Y’\\Z’\\1\end{bmatrix}=\begin{bmatrix}1&0&0&\Delta X\\0&1&0&\Delta Y\\0&0&1&\Delta Z\\0&0&0&1\end{bmatrix}\begin{bmatrix}X\\Y\\Z\\1\end{bmatrix}=\begin{bmatrix}X+\Delta X\\Y+\Delta Y\\Z+\Delta Z\\1\end{bmatrix}\)A translation can be inverted by applying the negative of the translation terms\(\begin{bmatrix}X\\Y\\Z\\1\end{bmatrix}=\begin{bmatrix}1&0&0&\Delta X\\0&1&0&\Delta Y\\0&0&1&\Delta Z\\0&0&0&1\end{bmatrix}^{-1}\begin{bmatrix}X’\\Y’\\Z’\\1\end{bmatrix}=\begin{bmatrix}1&0&0&-\Delta X\\0&1&0&-\Delta Y\\0&0&1&-\Delta Z\\0&0&0&1\end{bmatrix}\begin{bmatrix}X’\\Y’\\Z’\\1\end{bmatrix}\)RotationsIn \(\mathbb{R}^3\), the rotation of points about the origin are described by a \(3\times3\) matrix \(\mathbf{R}\). Valid rotation matrices obey the following properties:\(\mathrm{det}\left(\mathbf{R}\right) = +1\)\(\mathbf{R}^{-1}=\mathbf{R}^{\top}\)From these properties, both the columns and rows of \(\mathbf{R}\) are orthonormal.The rotation is applied by left-multipling the points by the rotation matrix.\(\begin{bmatrix}X’\\Y’\\Z’\end{bmatrix}=\begin{bmatrix}R_{11}&R_{12}&R_{13}\\R_{21}&R_{22}&R_{23}\\R_{31}&R_{32}&R_{33}\end{bmatrix}\begin{bmatrix}X\\Y\\Z\end{bmatrix}=\begin{bmatrix}R_{11}X+R_{12}Y+R_{13}Z\\R_{21}X+R_{22}Y+R_{23}Z\\R_{31}X+R_{32}Y+R_{33}Z\end{bmatrix}\)Rotations of 3D homogeneous may be defined by a \(4\times4\) matrix\(\begin{bmatrix}X’\\Y’\\Z’\\1\end{bmatrix}=\begin{bmatrix}R_{11}&R_{12}&R_{13}&0\\R_{21}&R_{22}&R_{23}&0\\R_{31}&R_{32}&R_{33}&0\\0&0&0&1\end{bmatrix}\begin{bmatrix}X\\Y\\Z\\1\end{bmatrix}\)Rotation of axes are defined by the inverse (transpose) of the rotation matrix transforming points by the same amount. A rotation of axes is also referred to as a pose. Unless specified, the rest of this page uses implies rotation to be a rotation of points about the origin.Basic RotationsA non-rotation is described by an identity matrix\(\mathbf{R}_{0}(\theta)=\begin{bmatrix}1&0&0\\0&1&0\\0&0&1\end{bmatrix}\)The right-handed rotation of points about the the \(X\), \(Y\), and \(Z\) axes are given by:\(\mathbf{R}_{X}(\theta)=\begin{bmatrix}1&0&0\\0&\cos\theta&-\sin\theta\\0&\sin\theta&\cos\theta\end{bmatrix}\)\(\mathbf{R}_{Y}(\theta)=\begin{bmatrix}\cos\theta&0&\sin\theta\\0&1&0\\-\sin\theta&0&\cos\theta\end{bmatrix}\)\(\mathbf{R}_{Z}(\theta)=\begin{bmatrix}\cos\theta&-\sin\theta&0\\\sin\theta&\cos\theta&0\\0&0&1\end{bmatrix}\)The inverse of these rotations are given by:\(\mathbf{R}^{-1}_{X}(\theta)=\mathbf{R}_{X}(-\theta)=\begin{bmatrix}1&0&0\\0&\cos\theta&\sin\theta\\0&-\sin\theta&\cos\theta\end{bmatrix}\)\(\mathbf{R}^{-1}_{Y}(\theta)=\mathbf{R}_{Y}(-\theta)=\begin{bmatrix}\cos\theta&0&-\sin\theta\\0&1&0\\\sin\theta&0&\cos\theta\end{bmatrix}\)\(\mathbf{R}^{-1}_{Z}(\theta)=\mathbf{R}_{Z}(-\theta)=\begin{bmatrix}\cos\theta&\sin\theta&0\\-\sin\theta&\cos\theta&0\\0&0&1\end{bmatrix}\)The rotation of axes by \(\theta\) radians is equivalent to a rotation of points by \(-\theta\) radians. The choices of rotation of bases or rotation of points and handedness of the rotation(s) should be specified to all relevant parties to avoid ambiguities in meaning. Chaining RotationsRotations may be combined in sequence by matrix-multiplying their rotation matrices. When performing sequences of rotations, later rotations are left-multiplied. For example a transform is defined by first rotating by \(\mathbf{R}_1\), then by \(\mathbf{R}_2\), and finally by \(\mathbf{R}_3\), the single rotation \(\mathbf{R}\) that describes the sequence of rotations is\(\mathbf{R}=\mathbf{R}_3\mathbf{R}_2\mathbf{R}_1\)Rotation-Translation CombinationsRotation-Translation MatricesA rotation about the origin followed by a translation may be described by a single \(4\times4\) matrix\(\begin{bmatrix}\mathbf{R}&\mathbf{t}\\\mathbf{0}^{\top}&1\end{bmatrix}\)where \(\mathbf{R}\) is the \(3\times3\) rotation matrix, \(\mathbf{t}\) is the \(3\times1\) translation, and \(\mathbf{0}\) is the \(3\times1\) vector of zeros.Since the last row of the \(4\times4\) rotation-translation matrix is always \(\begin{bmatrix}0&0&0&1\end{bmatrix}\), they are sometimes shorthanded to a \(3\times4\) augmented matrix\(\left[\begin{array}{c|c}\mathbf{R}&\mathbf{t}\end{array}\right]=\left[\begin{array}{ccc|c}R_{11}&R_{12}&R_{13}&t_{1}\\R_{21}&R_{22}&R_{23}&t_{2}\\R_{31}&R_{32}&R_{33}&t_{3}\end{array}\right]\)Note that when using this shorthand, matrix math is technically being broken as you cannot matrix multiply a \(3\times4\) matrix with a \(3\times4\) matrix. It is the implicit last row that is always the same that allows us to get away with this shorthand.Rotation-Translation InverseThe inverse of a rotation-translation matrix is given by\(\left[\begin{array}{c|c}\mathbf{R}&\mathbf{t}\end{array}\right]^{-1}=\left[\begin{array}{c|c}\mathbf{R}^{-1}&-\mathbf{R}^{-1}\mathbf{t}\end{array}\right]=\left[\begin{array}{c|c}\mathbf{R}^{\top}&-\mathbf{R}^{\top}\mathbf{t}\end{array}\right]\)Chaining Rotation-TranslationsJust like pure rotation matrices, later rotation-translation transforms are left multiplied. Given

To my DVR - once I killed that download, this one started going twice as fast. Duh. Unfortunately my speeds have been varied. I either get really slow speeds (under 100kb/s), or I get fairly good ones (~1.4mbps), but when I get good speeds it will download for a few minutes then the launcher will freeze up and I have to restart it. It's quite inconvenient... Purchased online at least 8 hours ago, still not even halfway through downloading Main Assets 1. Posted December 26, 2011 (edited) 1. game directory2. filename launcher.settings3. open with notepad4. scroll to bottom, edit "P2PEnabled": "true" 5. save with notepadfixed mine,now back to usual 2.65mb/s speedcos i'll be damned if i'm kept from playing what i paid for cos of minor screw ups, hope this works and see all you new guys in the game, enjoy! Furthermore download tcp optimizer, open it.open browser begin test, whatever download says in mbps go into tcp optimizer program set top scrolly bar to that, check optimal box. apply, reboot. Edited December 26, 2011 by Tolian I had the same issue, I started the download at 2100 and the game want downloaded patched and ready to play until 1700 the next day, which is a 20 hour download time lol. OMG TY!!!! that worked like a charm, also solved most of my "unable to reach patche server" issues as well, you sir should be commended!cheers 1. game directory2. filename launcher.settings3. open with notepad4. scroll to bottom, edit "P2PEnabled": "true" 5. save with notepadfixed mine,now back to usual 2.65mb/s speedcos i'll be damned if i'm kept from playing what i paid for cos of minor screw ups, hope this works and see all you new guys in the game, enjoy! Furthermore download tcp optimizer, open it.open browser begin test, whatever download says in mbps go into tcp optimizer program set top scrolly bar to that, check optimal box. apply, reboot.Thanks so much for posting this!!! This info should be a front-page news item on the main website... the p2penabled thing didn't work for me... Posted December 27, 2011 (edited) Me either. I rebuilt my system today with new MB, CPU and RAM I got for Christmas. Currently I am downloading at a whopping 75KB/s. This is awful. I have run several speed test and I am getting 10.20 Mbps. Any other suggestions would be greatly appreciated. Edited December 27, 2011 by Yerej 1. game directory2. filename launcher.settings3. open with notepad4. scroll to bottom, edit "P2PEnabled": "true" 5. save with notepadfixed mine,now back to usual 2.65mb/s speedcos i'll be damned if i'm kept from playing what i paid for cos of minor screw ups, hope this works and see all you

This function is defined in header file.[Mathematics] cos x = cos(x) [In C++ Programming]cos() prototype (As of C++ 11 standard)double cos(double x);float cos(float x);long double cos(long double x);double cos(T x); // Here, T is an integral type.cos() ParametersThe cos() function takes a single mandatory argument in radians.cos() Return valueThe cos() function returns the value in the range of [-1, 1]. The returned value is either in double, float, or long double.Note: To learn more about float and double in C++, visit C++ float and double.Example 1: How cos() works in C++?#include #include using namespace std;int main(){ double x = 0.5, result; result = cos(x); cout When you run the program, the output will be:cos(x) = 0.877583cos(x) = 0.906308Example 2: cos() function with integral type#include #include using namespace std;int main(){ int x = 1; double result; // result is in double result = cos(x); cout When you run the program, the output will be:cos(x) = 0.540302Also Read:C++ acos()