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So small that the concentration of HA is approximately the same as the concentration of A-The value of Ka indicates the extent of dissociationA high value of Ka means that:The equilibrium position lies to the rightThe acid is almost completely ionisedThe acid is strongly acidicA low value of Ka means that:The equilibrium position lies to the leftThe acid is only slightly ionised (there are mainly HA and only a few H+ and A- ions)The acid is weakly acidicSince Ka values of many weak acids are very low, pKa values are used instead to compare the strengths of weak acids with each otherpKa = -log10 KaThe less positive the pKa value the more acidic the acid isWorked ExampleCalculating the Ka & pKa of weak acidsCalculate the Ka and pKa values of 0.100 mol dm-3 ethanoic acid at 298K which forms 1.32 x 10-3 of H+ ions in solution.AnswerStep 1: Write down the equation for the partial dissociation of ethanoic acid:CH3COOH (aq) ⇌ H+ (aq) + CH3COO- (aq)Step 2: Write down the equilibrium expression to find Ka:Ka = H+ CH3COO-CH3COOH{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" role="math" height="47" width="119" alt="fraction numerator open square brackets straight H to the power of plus close square brackets space open square brackets CH subscript 3 COO to the power of minus close square brackets over denominator open square brackets CH subscript 3 COOH close square brackets end fraction">Step 3: Simplify the expression:The ratio of H+ to CH3COO- is 1:1The concentration of H+ and CH3COO- is, therefore, the sameThe equilibrium expression

Equals cell open parentheses x plus 1 close parentheses open parentheses 2 x plus 3 plus x minus 2 close parentheses end cell row blank equals cell open parentheses x plus 1 close parentheses open parentheses 3 x plus 1 close parentheses end cell end table" data-type="working">The whole expression is now fully simplified (but it's always worth checking!)(x+1)(3x+1){"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" role="math" height="22" width="117" alt="" data-type="finalAnswer">Expanding Triple BracketsHow do I expand three brackets?Multiply out any two brackets using a standard method and simplify this answer (collect any like terms)Replace the two brackets above with one long bracket containing the expanded resultExpand this long bracket with the third (unused) bracketThis step often looks like (x + a)(x2 + bx + c)Every term in the first bracket must be multiplied with every term in the second bracketThis leads to six terms A grid can often help to keep track of all six terms, for example (x + 2)(x2 + 3x + 1)add all the terms inside the grid (diagonals show like terms) to get x3 + 2x2 + 3x2 + 6x + x + 2collect like terms to get the final answer of x3 + 5x2 + 7x + 2Simplify the final answer by collecting like terms (if there are any)It helps to put negative terms in brackets when multiplyingWorked ExampleExpand 2x-3x+43x-1{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" role="math" height="22" width="163" alt="open parentheses 2 x minus 3 close parentheses open parentheses x plus 4 close parentheses open parentheses 3 x minus 1 close parentheses">.Start by expanding the first two sets of brackets and simplify by collecting 'like' terms2x-3x+4=2x×x+2x×4+-3×x+-3×4=2x2+8x-3x-12=2x2+5x-12{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" role="math" height="102" width="281" alt="table row blank blank cell open parentheses 2 x minus 3 close parentheses open parentheses x plus 4 close parentheses end cell row blank equals cell 2 x cross times x plus 2 x cross times 4 plus open parentheses negative 3 close parentheses cross times x plus open parentheses negative 3 close parentheses cross times 4 end cell row blank equals cell 2 x squared plus 8 x minus 3 x minus 12 end cell row blank equals cell 2 x squared plus 5 x minus 12 end cell end table" data-type="working">Rewrite the original expression with the first two brackets expanded2x2+5x-123x-1{"language":"en","fontFamily":"Times New Roman","fontSize":"18","autoformat":true}" role="math" height="23" width="167" alt="open parentheses 2 x squared plus 5 x minus 12 close parentheses open parentheses 3 x minus 1 close parentheses" data-type="working">Multiply all of the terms in the